Base | Representation |
---|---|
bin | 11101100100110010100100… |
… | …110011111001011110110001 |
3 | 122001112201102021201122121112 |
4 | 131210302210303321132301 |
5 | 114022043020443112043 |
6 | 1140350014114403105 |
7 | 36253234244243402 |
oct | 3544624463713661 |
9 | 561481367648545 |
10 | 130071554660273 |
11 | 384990447135a6 |
12 | 127088a4590495 |
13 | 5776905b1c455 |
14 | 24196d54659a9 |
15 | 10086d63ee518 |
hex | 764ca4cf97b1 |
130071554660273 has 2 divisors, whose sum is σ = 130071554660274. Its totient is φ = 130071554660272.
The previous prime is 130071554660231. The next prime is 130071554660279. The reversal of 130071554660273 is 372066455170031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76923547148449 + 53148007511824 = 8770607^2 + 7290268^2 .
It is a cyclic number.
It is not a de Polignac number, because 130071554660273 - 212 = 130071554656177 is a prime.
It is not a weakly prime, because it can be changed into another prime (130071554660279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65035777330136 + 65035777330137.
It is an arithmetic number, because the mean of its divisors is an integer number (65035777330137).
Almost surely, 2130071554660273 is an apocalyptic number.
It is an amenable number.
130071554660273 is a deficient number, since it is larger than the sum of its proper divisors (1).
130071554660273 is an equidigital number, since it uses as much as digits as its factorization.
130071554660273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3175200, while the sum is 50.
The spelling of 130071554660273 in words is "one hundred thirty trillion, seventy-one billion, five hundred fifty-four million, six hundred sixty thousand, two hundred seventy-three".
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