Base | Representation |
---|---|
bin | 11000001110101000… |
… | …10101011101010001 |
3 | 1020120112020021001221 |
4 | 30013110111131101 |
5 | 203114431020134 |
6 | 5550423325041 |
7 | 640225253251 |
oct | 140724253521 |
9 | 36515207057 |
10 | 13007673169 |
11 | 5575546417 |
12 | 26302b0781 |
13 | 12c3b5a43a |
14 | 8b57a5961 |
15 | 511e6a5b4 |
hex | 307515751 |
13007673169 has 2 divisors, whose sum is σ = 13007673170. Its totient is φ = 13007673168.
The previous prime is 13007673157. The next prime is 13007673209. The reversal of 13007673169 is 96137670031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12738056769 + 269616400 = 112863^2 + 16420^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13007673169 is a prime.
It is a super-2 number, since 2×130076731692 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13007673109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6503836584 + 6503836585.
It is an arithmetic number, because the mean of its divisors is an integer number (6503836585).
Almost surely, 213007673169 is an apocalyptic number.
It is an amenable number.
13007673169 is a deficient number, since it is larger than the sum of its proper divisors (1).
13007673169 is an equidigital number, since it uses as much as digits as its factorization.
13007673169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 142884, while the sum is 43.
The spelling of 13007673169 in words is "thirteen billion, seven million, six hundred seventy-three thousand, one hundred sixty-nine".
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