1300999993 has 2 divisors, whose sum is σ = 1300999994. Its totient is φ = 1300999992.

The previous prime is 1300999981. The next prime is 1301000039. The reversal of 1300999993 is 3999990031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1172925504 + 128074489 = 34248^2 + 11317^2 .

It is an emirp because it is prime and its reverse (3999990031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300999993 - 2⁹ = 1300999481 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1300999993.

It is not a weakly prime, because it can be changed into another prime (1300999913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650499996 + 650499997.

It is an arithmetic number, because the mean of its divisors is an integer number (650499997).

Almost surely, 2^1300999993 is an apocalyptic number.

It is an amenable number.

1300999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300999993 is an equidigital number, since it uses as much as digits as its factorization.

1300999993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 531441, while the sum is 52.

The square root of 1300999993 is about 36069.3774967076. The cubic root of 1300999993 is about 1091.6726537079.

The spelling of 1300999993 in words is "one billion, three hundred million, nine hundred ninety-nine thousand, nine hundred ninety-three".