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13010050489 is a prime number
BaseRepresentation
bin11000001110111010…
…11001110110111001
31020120200201001010211
430013131121312321
5203121033103424
65550550311121
7640254414232
oct140735316671
936520631124
1013010050489
11557691a547
1226310584a1
1312c44b0537
148b5c24089
15512289b94
hex307759db9

13010050489 has 2 divisors, whose sum is σ = 13010050490. Its totient is φ = 13010050488.

The previous prime is 13010050483. The next prime is 13010050541. The reversal of 13010050489 is 98405001031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12030360489 + 979690000 = 109683^2 + 31300^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010050489 - 229 = 12473179577 is a prime.

It is a super-2 number, since 2×130100504892 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13010050489.

It is not a weakly prime, because it can be changed into another prime (13010050483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505025244 + 6505025245.

It is an arithmetic number, because the mean of its divisors is an integer number (6505025245).

Almost surely, 213010050489 is an apocalyptic number.

It is an amenable number.

13010050489 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010050489 is an equidigital number, since it uses as much as digits as its factorization.

13010050489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 31.

The spelling of 13010050489 in words is "thirteen billion, ten million, fifty thousand, four hundred eighty-nine".