1301013111331 has 4 divisors (see below), whose sum is σ = 1301109804072. Its totient is φ = 1300916418592.

The previous prime is 1301013111317. The next prime is 1301013111337. The reversal of 1301013111331 is 1331113101031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301013111331 - 2²¹ = 1301011014179 is a prime.

It is a super-2 number, since 2×1301013111331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301013111299 and 1301013111308.

It is not an unprimeable number, because it can be changed into a prime (1301013111337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48326185 + ... + 48353098.

It is an arithmetic number, because the mean of its divisors is an integer number (325277451018).

Almost surely, 2^{1301013111331} is an apocalyptic number.

1301013111331 is a deficient number, since it is larger than the sum of its proper divisors (96692741).

1301013111331 is an equidigital number, since it uses as much as digits as its factorization.

1301013111331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96692740.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1301013111331 its reverse (1331113101031), we get a palindrome (2632126212362).

The spelling of 1301013111331 in words is "one trillion, three hundred one billion, thirteen million, one hundred eleven thousand, three hundred thirty-one".