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130101507217147 = 295344057401699
BaseRepresentation
bin11101100101001110011110…
…000111110101011011111011
3122001122120201201202012020211
4131211032132013311123323
5114023040341321422042
61140411450213531551
736255344426624164
oct3545163607653373
9561576651665224
10130101507217147
11384aa8150a2934
1212712663643bb7
13577969a412b9b
14241ad3748076b
15100938aca6017
hex76539e1f56fb

130101507217147 has 4 divisors (see below), whose sum is σ = 130145564621800. Its totient is φ = 130057449812496.

The previous prime is 130101507217091. The next prime is 130101507217159. The reversal of 130101507217147 is 741712705101031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130101507217147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130101507211147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22028697897 + ... + 22028703802.

It is an arithmetic number, because the mean of its divisors is an integer number (32536391155450).

Almost surely, 2130101507217147 is an apocalyptic number.

130101507217147 is a deficient number, since it is larger than the sum of its proper divisors (44057404653).

130101507217147 is an equidigital number, since it uses as much as digits as its factorization.

130101507217147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44057404652.

The product of its (nonzero) digits is 41160, while the sum is 40.

The spelling of 130101507217147 in words is "one hundred thirty trillion, one hundred one billion, five hundred seven million, two hundred seventeen thousand, one hundred forty-seven".

Divisors: 1 2953 44057401699 130101507217147