Base | Representation |
---|---|
bin | 11101100101001110011110… |
… | …000111110101011011111011 |
3 | 122001122120201201202012020211 |
4 | 131211032132013311123323 |
5 | 114023040341321422042 |
6 | 1140411450213531551 |
7 | 36255344426624164 |
oct | 3545163607653373 |
9 | 561576651665224 |
10 | 130101507217147 |
11 | 384aa8150a2934 |
12 | 12712663643bb7 |
13 | 577969a412b9b |
14 | 241ad3748076b |
15 | 100938aca6017 |
hex | 76539e1f56fb |
130101507217147 has 4 divisors (see below), whose sum is σ = 130145564621800. Its totient is φ = 130057449812496.
The previous prime is 130101507217091. The next prime is 130101507217159. The reversal of 130101507217147 is 741712705101031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130101507217147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130101507211147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22028697897 + ... + 22028703802.
It is an arithmetic number, because the mean of its divisors is an integer number (32536391155450).
Almost surely, 2130101507217147 is an apocalyptic number.
130101507217147 is a deficient number, since it is larger than the sum of its proper divisors (44057404653).
130101507217147 is an equidigital number, since it uses as much as digits as its factorization.
130101507217147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44057404652.
The product of its (nonzero) digits is 41160, while the sum is 40.
The spelling of 130101507217147 in words is "one hundred thirty trillion, one hundred one billion, five hundred seven million, two hundred seventeen thousand, one hundred forty-seven".
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