Base | Representation |
---|---|
bin | 10010111011101011000… |
… | …110010110011111000001 |
3 | 11121101011122000002122100 |
4 | 102323223012112133001 |
5 | 132303444223342423 |
6 | 2433403220501013 |
7 | 162665412136635 |
oct | 22735306263701 |
9 | 4541148002570 |
10 | 1301024434113 |
11 | 461841414758 |
12 | 19019254a769 |
13 | 958bc40b081 |
14 | 46d81656dc5 |
15 | 23c98d31343 |
hex | 12eeb1967c1 |
1301024434113 has 24 divisors (see below), whose sum is σ = 1881468089280. Its totient is φ = 866329843680.
The previous prime is 1301024434103. The next prime is 1301024434159. The reversal of 1301024434113 is 3114344201031.
1301024434113 is a `hidden beast` number, since 1 + 3 + 0 + 1 + 0 + 244 + 3 + 411 + 3 = 666.
It is not a de Polignac number, because 1301024434113 - 26 = 1301024434049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1301024434103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36292108 + ... + 36327938.
It is an arithmetic number, because the mean of its divisors is an integer number (78394503720).
Almost surely, 21301024434113 is an apocalyptic number.
It is an amenable number.
1301024434113 is a deficient number, since it is larger than the sum of its proper divisors (580443655167).
1301024434113 is a wasteful number, since it uses less digits than its factorization.
1301024434113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40469 (or 40466 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1301024434113 its reverse (3114344201031), we get a palindrome (4415368635144).
The spelling of 1301024434113 in words is "one trillion, three hundred one billion, twenty-four million, four hundred thirty-four thousand, one hundred thirteen".
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