Base | Representation |
---|---|
bin | 11101100101001111111101… |
… | …000100101101000101110011 |
3 | 122001122201211202021201212211 |
4 | 131211033331010231011303 |
5 | 114023102122124411201 |
6 | 1140412312241432551 |
7 | 36255432052212412 |
oct | 3545177504550563 |
9 | 561581752251784 |
10 | 130103100232051 |
11 | 38500462333581 |
12 | 12712a2903b757 |
13 | 577989247145b |
14 | 241b048c77479 |
15 | 1009430a75651 |
hex | 7653fd12d173 |
130103100232051 has 2 divisors, whose sum is σ = 130103100232052. Its totient is φ = 130103100232050.
The previous prime is 130103100231997. The next prime is 130103100232069. The reversal of 130103100232051 is 150232001301031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130103100232051 - 221 = 130103098134899 is a prime.
It is a super-2 number, since 2×1301031002320512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130103100272051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051550116025 + 65051550116026.
It is an arithmetic number, because the mean of its divisors is an integer number (65051550116026).
Almost surely, 2130103100232051 is an apocalyptic number.
130103100232051 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103100232051 is an equidigital number, since it uses as much as digits as its factorization.
130103100232051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 130103100232051 its reverse (150232001301031), we get a palindrome (280335101533082).
The spelling of 130103100232051 in words is "one hundred thirty trillion, one hundred three billion, one hundred million, two hundred thirty-two thousand, fifty-one".
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