Base | Representation |
---|---|
bin | 11101100101010110101100… |
… | …001000001010110010001011 |
3 | 122001200102111202100201102011 |
4 | 131211112230020022302023 |
5 | 114023211430010321303 |
6 | 1140415510022120351 |
7 | 36256106215230421 |
oct | 3545265410126213 |
9 | 561612452321364 |
10 | 130110332120203 |
11 | 38503533570146 |
12 | 12714306b800b7 |
13 | 577a475817c06 |
14 | 241b533517111 |
15 | 10097058e716d |
hex | 7655ac20ac8b |
130110332120203 has 2 divisors, whose sum is σ = 130110332120204. Its totient is φ = 130110332120202.
The previous prime is 130110332120161. The next prime is 130110332120257. The reversal of 130110332120203 is 302021233011031.
It is a weak prime.
It is an emirp because it is prime and its reverse (302021233011031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130110332120203 is a prime.
It is a super-2 number, since 2×1301103321202032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130110332120003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055166060101 + 65055166060102.
It is an arithmetic number, because the mean of its divisors is an integer number (65055166060102).
Almost surely, 2130110332120203 is an apocalyptic number.
130110332120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
130110332120203 is an equidigital number, since it uses as much as digits as its factorization.
130110332120203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 130110332120203 its reverse (302021233011031), we get a palindrome (432131565131234).
The spelling of 130110332120203 in words is "one hundred thirty trillion, one hundred ten billion, three hundred thirty-two million, one hundred twenty thousand, two hundred three".
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