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130111003537 is a prime number
BaseRepresentation
bin111100100101100111…
…0000101101110010001
3110102211122210210211221
41321023032011232101
54112431404103122
6135434442205041
712254162165554
oct1711316055621
9412748723757
10130111003537
11501a82a6799
1221271ab3781
13c366b9b8b8
14642412269b
1535b798d6c7
hex1e4b385b91

130111003537 has 2 divisors, whose sum is σ = 130111003538. Its totient is φ = 130111003536.

The previous prime is 130111003523. The next prime is 130111003553. The reversal of 130111003537 is 735300111031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130064094736 + 46908801 = 360644^2 + 6849^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130111003537 is a prime.

It is not a weakly prime, because it can be changed into another prime (130111003567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055501768 + 65055501769.

It is an arithmetic number, because the mean of its divisors is an integer number (65055501769).

Almost surely, 2130111003537 is an apocalyptic number.

It is an amenable number.

130111003537 is a deficient number, since it is larger than the sum of its proper divisors (1).

130111003537 is an equidigital number, since it uses as much as digits as its factorization.

130111003537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 945, while the sum is 25.

Adding to 130111003537 its reverse (735300111031), we get a palindrome (865411114568).

The spelling of 130111003537 in words is "one hundred thirty billion, one hundred eleven million, three thousand, five hundred thirty-seven".