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130111043203 = 1229105867407
BaseRepresentation
bin111100100101100111…
…0001111011010000011
3110102211122212211021001
41321023032033122003
54112431411340303
6135434443112431
712254162422321
oct1711316173203
9412748784231
10130111043203
11501a8323579
1221271b12717
13c366bb397b
146424132d11
1535b799a31d
hex1e4b38f683

130111043203 has 4 divisors (see below), whose sum is σ = 130216911840. Its totient is φ = 130005174568.

The previous prime is 130111043201. The next prime is 130111043207. The reversal of 130111043203 is 302340111031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 302340111031 = 743191444433.

It is a cyclic number.

It is not a de Polignac number, because 130111043203 - 21 = 130111043201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130111043201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52932475 + ... + 52934932.

It is an arithmetic number, because the mean of its divisors is an integer number (32554227960).

Almost surely, 2130111043203 is an apocalyptic number.

130111043203 is a deficient number, since it is larger than the sum of its proper divisors (105868637).

130111043203 is a wasteful number, since it uses less digits than its factorization.

130111043203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105868636.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 130111043203 its reverse (302340111031), we get a palindrome (432451154234).

The spelling of 130111043203 in words is "one hundred thirty billion, one hundred eleven million, forty-three thousand, two hundred three".

Divisors: 1 1229 105867407 130111043203