Base | Representation |
---|---|
bin | 1011110101010110001101… |
… | …0111110000110110011011 |
3 | 1201001211222112121020022101 |
4 | 2331111203113300312123 |
5 | 3201133240004111441 |
6 | 43401121043304231 |
7 | 2512010521453345 |
oct | 275254327606633 |
9 | 51054875536271 |
10 | 13011123113371 |
11 | 4166a93886479 |
12 | 156178697b077 |
13 | 734c36259ac6 |
14 | 32da553c2295 |
15 | 1786b0e44231 |
hex | bd5635f0d9b |
13011123113371 has 2 divisors, whose sum is σ = 13011123113372. Its totient is φ = 13011123113370.
The previous prime is 13011123113311. The next prime is 13011123113377. The reversal of 13011123113371 is 17331132111031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13011123113371 - 27 = 13011123113243 is a prime.
It is not a weakly prime, because it can be changed into another prime (13011123113377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505561556685 + 6505561556686.
It is an arithmetic number, because the mean of its divisors is an integer number (6505561556686).
Almost surely, 213011123113371 is an apocalyptic number.
13011123113371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011123113371 is an equidigital number, since it uses as much as digits as its factorization.
13011123113371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 28.
The spelling of 13011123113371 in words is "thirteen trillion, eleven billion, one hundred twenty-three million, one hundred thirteen thousand, three hundred seventy-one".
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