1301113311001 has 4 divisors (see below), whose sum is σ = 1486986641152. Its totient is φ = 1115239980852.

The previous prime is 1301113310969. The next prime is 1301113311037. The reversal of 1301113311001 is 1001133111031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301113311001 - 2⁵ = 1301113310969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301113311301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92936665065 + ... + 92936665078.

It is an arithmetic number, because the mean of its divisors is an integer number (371746660288).

Almost surely, 2^{1301113311001} is an apocalyptic number.

It is an amenable number.

1301113311001 is a deficient number, since it is larger than the sum of its proper divisors (185873330151).

1301113311001 is an equidigital number, since it uses as much as digits as its factorization.

1301113311001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 185873330150.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 1301113311001 its reverse (1001133111031), we get a palindrome (2302246422032).

The spelling of 1301113311001 in words is "one trillion, three hundred one billion, one hundred thirteen million, three hundred eleven thousand, one".