1301120000121 has 4 divisors (see below), whose sum is σ = 1734826666832. Its totient is φ = 867413333412.

The previous prime is 1301120000113. The next prime is 1301120000177. The reversal of 1301120000121 is 1210000211031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1301120000121 - 2³ = 1301120000113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301120000097 and 1301120000106.

It is not an unprimeable number, because it can be changed into a prime (1301120005121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216853333351 + ... + 216853333356.

It is an arithmetic number, because the mean of its divisors is an integer number (433706666708).

Almost surely, 2^{1301120000121} is an apocalyptic number.

It is an amenable number.

1301120000121 is a deficient number, since it is larger than the sum of its proper divisors (433706666711).

1301120000121 is an equidigital number, since it uses as much as digits as its factorization.

1301120000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 433706666710.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 1301120000121 its reverse (1210000211031), we get a palindrome (2511120211152).

The spelling of 1301120000121 in words is "one trillion, three hundred one billion, one hundred twenty million, one hundred twenty-one", and thus it is an aban number.