Base | Representation |
---|---|
bin | 11101100101011000011011… |
… | …101001110100100101000011 |
3 | 122001200121100011011002100221 |
4 | 131211120123221310211003 |
5 | 114023224243010304443 |
6 | 1140420415422123511 |
7 | 36256203455243005 |
oct | 3545303351644503 |
9 | 561617304132327 |
10 | 130112203213123 |
11 | 38504303771a2a |
12 | 12714749720597 |
13 | 577a6b336a0a1 |
14 | 241b66dc18375 |
15 | 10097b4ce4eed |
hex | 76561ba74943 |
130112203213123 has 2 divisors, whose sum is σ = 130112203213124. Its totient is φ = 130112203213122.
The previous prime is 130112203213081. The next prime is 130112203213133. The reversal of 130112203213123 is 321312302211031.
It is a strong prime.
It is an emirp because it is prime and its reverse (321312302211031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130112203213123 is a prime.
It is not a weakly prime, because it can be changed into another prime (130112203213133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056101606561 + 65056101606562.
It is an arithmetic number, because the mean of its divisors is an integer number (65056101606562).
Almost surely, 2130112203213123 is an apocalyptic number.
130112203213123 is a deficient number, since it is larger than the sum of its proper divisors (1).
130112203213123 is an equidigital number, since it uses as much as digits as its factorization.
130112203213123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 130112203213123 its reverse (321312302211031), we get a palindrome (451424505424154).
The spelling of 130112203213123 in words is "one hundred thirty trillion, one hundred twelve billion, two hundred three million, two hundred thirteen thousand, one hundred twenty-three".
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