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13011303102113 = 195456312550729
BaseRepresentation
bin1011110101010110111000…
…0110010111011010100001
31201001212110002021121110002
42331111232012113122201
53201134122043231423
643401150553145345
72512015135364021
oct275255606273241
951055402247402
1013011303102113
1141670764406a8
1215618170bb255
13734c64628814
1432da71275a81
151786c1b49228
hexbd56e1976a1

13011303102113 has 8 divisors (see below), whose sum is σ = 13696360634400. Its totient is φ = 12326270780448.

The previous prime is 13011303102107. The next prime is 13011303102131. The reversal of 13011303102113 is 31120130311031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13011303102113 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13011303102103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5238668 + ... + 7312061.

It is an arithmetic number, because the mean of its divisors is an integer number (1712045079300).

Almost surely, 213011303102113 is an apocalyptic number.

It is an amenable number.

13011303102113 is a deficient number, since it is larger than the sum of its proper divisors (685057532287).

13011303102113 is a wasteful number, since it uses less digits than its factorization.

13011303102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12605311.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 13011303102113 its reverse (31120130311031), we get a palindrome (44131433413144).

The spelling of 13011303102113 in words is "thirteen trillion, eleven billion, three hundred three million, one hundred two thousand, one hundred thirteen".

Divisors: 1 19 54563 1036697 12550729 238463851 684805426427 13011303102113