Base | Representation |
---|---|
bin | 10010111011110001011… |
… | …110000110001011100011 |
3 | 11121101110002010120101001 |
4 | 102323301132012023203 |
5 | 132304204104301313 |
6 | 2433421555452431 |
7 | 163001150520445 |
oct | 22736136061343 |
9 | 4541402116331 |
10 | 1301131322083 |
11 | 46189679021a |
12 | 1902022b7117 |
13 | 959085c3aa8 |
14 | 46d9191c495 |
15 | 23ca33e6add |
hex | 12ef17862e3 |
1301131322083 has 2 divisors, whose sum is σ = 1301131322084. Its totient is φ = 1301131322082.
The previous prime is 1301131322039. The next prime is 1301131322129. The reversal of 1301131322083 is 3802231311031.
It is a weak prime.
It is an emirp because it is prime and its reverse (3802231311031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1301131322083 - 213 = 1301131313891 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301131322683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650565661041 + 650565661042.
It is an arithmetic number, because the mean of its divisors is an integer number (650565661042).
Almost surely, 21301131322083 is an apocalyptic number.
1301131322083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301131322083 is an equidigital number, since it uses as much as digits as its factorization.
1301131322083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 1301131322083 in words is "one trillion, three hundred one billion, one hundred thirty-one million, three hundred twenty-two thousand, eighty-three".
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