Base | Representation |
---|---|
bin | 1011110101010110111101… |
… | …0110001101110001000001 |
3 | 1201001212111112200001202100 |
4 | 2331111233112031301001 |
5 | 3201134142423042423 |
6 | 43401153021541013 |
7 | 2512015511324166 |
oct | 275255726156101 |
9 | 51055445601670 |
10 | 13011324034113 |
11 | 4167087238179 |
12 | 1561822114769 |
13 | 734c68a77212 |
14 | 32da73d6406d |
15 | 1786c38d1343 |
hex | bd56f58dc41 |
13011324034113 has 12 divisors (see below), whose sum is σ = 18816970856320. Its totient is φ = 8663676265656.
The previous prime is 13011324034063. The next prime is 13011324034139. The reversal of 13011324034113 is 31143042311031.
13011324034113 is a `hidden beast` number, since 1 + 3 + 0 + 1 + 1 + 3 + 240 + 3 + 411 + 3 = 666.
It is not a de Polignac number, because 13011324034113 - 217 = 13011323903041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13011324034613) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 878305273 + ... + 878320086.
Almost surely, 213011324034113 is an apocalyptic number.
It is an amenable number.
13011324034113 is a deficient number, since it is larger than the sum of its proper divisors (5805646822207).
13011324034113 is a wasteful number, since it uses less digits than its factorization.
13011324034113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1756626188 (or 1756626185 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 13011324034113 its reverse (31143042311031), we get a palindrome (44154366345144).
The spelling of 13011324034113 in words is "thirteen trillion, eleven billion, three hundred twenty-four million, thirty-four thousand, one hundred thirteen".
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