Base | Representation |
---|---|
bin | 10010111011110001101… |
… | …000010111011000010001 |
3 | 11121101110021012022221112 |
4 | 102323301220113120101 |
5 | 132304210301421334 |
6 | 2433422133303105 |
7 | 163001212431506 |
oct | 22736150273021 |
9 | 4541407168845 |
10 | 1301134013969 |
11 | 461898259719 |
12 | 190203194a95 |
13 | 9590902711a |
14 | 46d9201d4ad |
15 | 23ca37794ce |
hex | 12ef1a17611 |
1301134013969 has 2 divisors, whose sum is σ = 1301134013970. Its totient is φ = 1301134013968.
The previous prime is 1301134013941. The next prime is 1301134014007. The reversal of 1301134013969 is 9693104311031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1300512160000 + 621853969 = 1140400^2 + 24937^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301134013969 is a prime.
It is a super-2 number, since 2×13011340139692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1301134013269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650567006984 + 650567006985.
It is an arithmetic number, because the mean of its divisors is an integer number (650567006985).
Almost surely, 21301134013969 is an apocalyptic number.
It is an amenable number.
1301134013969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301134013969 is an equidigital number, since it uses as much as digits as its factorization.
1301134013969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 41.
The spelling of 1301134013969 in words is "one trillion, three hundred one billion, one hundred thirty-four million, thirteen thousand, nine hundred sixty-nine".
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