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13011403433001 = 310740533967081
BaseRepresentation
bin1011110101010111010000…
…0101000110010000101001
31201001212201002001221112220
42331111310011012100221
53201134323234324001
643401204535424253
72512020464234631
oct275256405062051
951055632057486
1013011403433001
114167118038796
121561844825089
13734c7c356acc
1432da807116c1
151786ca866c36
hexbd574146429

13011403433001 has 8 divisors (see below), whose sum is σ = 17510673779424. Its totient is φ = 8593201020960.

The previous prime is 13011403432961. The next prime is 13011403433051. The reversal of 13011403433001 is 10033430411031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13011403433001 - 210 = 13011403431977 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13011403433051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20266983220 + ... + 20266983861.

It is an arithmetic number, because the mean of its divisors is an integer number (2188834222428).

Almost surely, 213011403433001 is an apocalyptic number.

It is an amenable number.

13011403433001 is a deficient number, since it is larger than the sum of its proper divisors (4499270346423).

13011403433001 is a wasteful number, since it uses less digits than its factorization.

13011403433001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40533967191.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 13011403433001 its reverse (10033430411031), we get a palindrome (23044833844032).

The spelling of 13011403433001 in words is "thirteen trillion, eleven billion, four hundred three million, four hundred thirty-three thousand, one".

Divisors: 1 3 107 321 40533967081 121601901243 4337134477667 13011403433001