Base | Representation |
---|---|
bin | 1011110101010111110100… |
… | …0100110100000101010001 |
3 | 1201001220002121001111112121 |
4 | 2331111331010310011101 |
5 | 3201140130403302424 |
6 | 43401231530254241 |
7 | 2512024306110226 |
oct | 275257504640521 |
9 | 51056077044477 |
10 | 13011554353489 |
11 | 416719524956a |
12 | 1561887287381 |
13 | 734ca46b8983 |
14 | 32da9679994d |
15 | 1786d8c28ee4 |
hex | bd57d134151 |
13011554353489 has 2 divisors, whose sum is σ = 13011554353490. Its totient is φ = 13011554353488.
The previous prime is 13011554353423. The next prime is 13011554353559. The reversal of 13011554353489 is 98435345511031.
13011554353489 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9254780055889 + 3756774297600 = 3042167^2 + 1938240^2 .
It is a cyclic number.
It is not a de Polignac number, because 13011554353489 - 227 = 13011420135761 is a prime.
It is not a weakly prime, because it can be changed into another prime (13011554350489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505777176744 + 6505777176745.
It is an arithmetic number, because the mean of its divisors is an integer number (6505777176745).
Almost surely, 213011554353489 is an apocalyptic number.
It is an amenable number.
13011554353489 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011554353489 is an equidigital number, since it uses as much as digits as its factorization.
13011554353489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888000, while the sum is 52.
The spelling of 13011554353489 in words is "thirteen trillion, eleven billion, five hundred fifty-four million, three hundred fifty-three thousand, four hundred eighty-nine".
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