Base | Representation |
---|---|
bin | 111100100101111000… |
… | …0011111000011110011 |
3 | 110102212021202220101211 |
4 | 1321023300133003303 |
5 | 4112441211121321 |
6 | 135435403340551 |
7 | 12254331631336 |
oct | 1711360370363 |
9 | 412767686354 |
10 | 130120020211 |
11 | 502023a5095 |
12 | 21274b21757 |
13 | c368a079cc |
14 | 64253cc61d |
15 | 35b86700e1 |
hex | 1e4bc1f0f3 |
130120020211 has 16 divisors (see below), whose sum is σ = 137041917120. Its totient is φ = 123417423360.
The previous prime is 130120020193. The next prime is 130120020227. The reversal of 130120020211 is 112020021031.
It is a cyclic number.
It is not a de Polignac number, because 130120020211 - 221 = 130117923059 is a prime.
It is a super-2 number, since 2×1301200202112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130120020191 and 130120020200.
It is not an unprimeable number, because it can be changed into a prime (130120020241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44466 + ... + 512071.
It is an arithmetic number, because the mean of its divisors is an integer number (8565119820).
Almost surely, 2130120020211 is an apocalyptic number.
130120020211 is a deficient number, since it is larger than the sum of its proper divisors (6921896909).
130120020211 is an equidigital number, since it uses as much as digits as its factorization.
130120020211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 556734.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 130120020211 its reverse (112020021031), we get a palindrome (242140041242).
The spelling of 130120020211 in words is "one hundred thirty billion, one hundred twenty million, twenty thousand, two hundred eleven".
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