130120040240121 has 4 divisors (see below), whose sum is σ = 173493386986832. Its totient is φ = 86746693493412.

The previous prime is 130120040240111. The next prime is 130120040240147. The reversal of 130120040240121 is 121042040021031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-130120040240121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130120040240101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21686673373351 + ... + 21686673373356.

It is an arithmetic number, because the mean of its divisors is an integer number (43373346746708).

Almost surely, 2^{130120040240121} is an apocalyptic number.

It is an amenable number.

130120040240121 is a deficient number, since it is larger than the sum of its proper divisors (43373346746711).

130120040240121 is an equidigital number, since it uses as much as digits as its factorization.

130120040240121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43373346746710.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 130120040240121 its reverse (121042040021031), we get a palindrome (251162080261152).

The spelling of 130120040240121 in words is "one hundred thirty trillion, one hundred twenty billion, forty million, two hundred forty thousand, one hundred twenty-one".