1301204211481 has 2 divisors, whose sum is σ = 1301204211482. Its totient is φ = 1301204211480.

The previous prime is 1301204211397. The next prime is 1301204211487. The reversal of 1301204211481 is 1841124021031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 866770310025 + 434433901456 = 931005^2 + 659116^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301204211481 - 2¹⁵ = 1301204178713 is a prime.

It is a super-3 number, since 3×1301204211481³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1301204211487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650602105740 + 650602105741.

It is an arithmetic number, because the mean of its divisors is an integer number (650602105741).

Almost surely, 2^{1301204211481} is an apocalyptic number.

It is an amenable number.

1301204211481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301204211481 is an equidigital number, since it uses as much as digits as its factorization.

1301204211481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 28.

The spelling of 1301204211481 in words is "one trillion, three hundred one billion, two hundred four million, two hundred eleven thousand, four hundred eighty-one".