130120444401 has 4 divisors (see below), whose sum is σ = 173493925872. Its totient is φ = 86746962932.

The previous prime is 130120444369. The next prime is 130120444409. The reversal of 130120444401 is 104444021031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130120444401 - 2⁵ = 130120444369 is a prime.

It is a super-2 number, since 2×130120444401² (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130120444409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21686740731 + ... + 21686740736.

It is an arithmetic number, because the mean of its divisors is an integer number (43373481468).

Almost surely, 2^130120444401 is an apocalyptic number.

It is an amenable number.

130120444401 is a deficient number, since it is larger than the sum of its proper divisors (43373481471).

130120444401 is an equidigital number, since it uses as much as digits as its factorization.

130120444401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43373481470.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 130120444401 its reverse (104444021031), we get a palindrome (234564465432).

The spelling of 130120444401 in words is "one hundred thirty billion, one hundred twenty million, four hundred forty-four thousand, four hundred one".