Base | Representation |
---|---|
bin | 1011110101011001111001… |
… | …0001100001011010010010 |
3 | 1201001221112102002222210202 |
4 | 2331112132101201122102 |
5 | 3201142301000124020 |
6 | 43401403104255202 |
7 | 2512044151261226 |
oct | 275263621413222 |
9 | 51057472088722 |
10 | 13012111333010 |
11 | 4167450693519 |
12 | 1561a01911502 |
13 | 735062c00c5a |
14 | 32db0a744786 |
15 | 17871ca99e75 |
hex | bd59e461692 |
13012111333010 has 16 divisors (see below), whose sum is σ = 23422573763136. Its totient is φ = 5204672674608.
The previous prime is 13012111333007. The next prime is 13012111333021. The reversal of 13012111333010 is 1033311121031.
13012111333010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×130121113330103 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21164102 + ... + 21770241.
It is an arithmetic number, because the mean of its divisors is an integer number (1463910860196).
Almost surely, 213012111333010 is an apocalyptic number.
13012111333010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13012111333010 is a deficient number, since it is larger than the sum of its proper divisors (10410462430126).
13012111333010 is a wasteful number, since it uses less digits than its factorization.
13012111333010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42964657.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 13012111333010 its reverse (1033311121031), we get a palindrome (14045422454041).
The spelling of 13012111333010 in words is "thirteen trillion, twelve billion, one hundred eleven million, three hundred thirty-three thousand, ten".
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