Base | Representation |
---|---|
bin | 11101100101100000101111… |
… | …001001111011100011100011 |
3 | 122001201110100121021122212011 |
4 | 131211200233021323203203 |
5 | 114023401023301111003 |
6 | 1140424452323013351 |
7 | 36256640443431103 |
oct | 3545405711734343 |
9 | 561643317248764 |
10 | 130121120332003 |
11 | 3850806a1a4369 |
12 | 12716417b0a257 |
13 | 577b4a48bb7a8 |
14 | 241bc78217203 |
15 | 1009b37a9e46d |
hex | 76582f27b8e3 |
130121120332003 has 4 divisors (see below), whose sum is σ = 132889654807200. Its totient is φ = 127352585856808.
The previous prime is 130121120331977. The next prime is 130121120332009. The reversal of 130121120332003 is 300233021121031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130121120332003 - 217 = 130121120200931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130121120332009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1384267237528 + ... + 1384267237621.
It is an arithmetic number, because the mean of its divisors is an integer number (33222413701800).
Almost surely, 2130121120332003 is an apocalyptic number.
130121120332003 is a deficient number, since it is larger than the sum of its proper divisors (2768534475197).
130121120332003 is an equidigital number, since it uses as much as digits as its factorization.
130121120332003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2768534475196.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 130121120332003 its reverse (300233021121031), we get a palindrome (430354141453034).
The spelling of 130121120332003 in words is "one hundred thirty trillion, one hundred twenty-one billion, one hundred twenty million, three hundred thirty-two thousand, three".
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