13012153044001 has 4 divisors (see below), whose sum is σ = 13012187715504. Its totient is φ = 13012118372500.

The previous prime is 13012153043839. The next prime is 13012153044031. The reversal of 13012153044001 is 10044035121031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13012153044001 - 2³³ = 13003563109409 is a prime.

It is a super-2 number, since 2×13012153044001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13012153044031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16766575 + ... + 17525476.

It is an arithmetic number, because the mean of its divisors is an integer number (3253046928876).

Almost surely, 2^{13012153044001} is an apocalyptic number.

It is an amenable number.

13012153044001 is a deficient number, since it is larger than the sum of its proper divisors (34671503).

13012153044001 is an equidigital number, since it uses as much as digits as its factorization.

13012153044001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34671502.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13012153044001 its reverse (10044035121031), we get a palindrome (23056188165032).

The spelling of 13012153044001 in words is "thirteen trillion, twelve billion, one hundred fifty-three million, forty-four thousand, one".