Base | Representation |
---|---|
bin | 111100100101111100… |
… | …1001110011010011011 |
3 | 110102212110002022012211 |
4 | 1321023321032122123 |
5 | 4112442302430243 |
6 | 135435524415551 |
7 | 12254360253064 |
oct | 1711371163233 |
9 | 412773068184 |
10 | 130122311323 |
11 | 5020371a474 |
12 | 212758475b7 |
13 | c36932a7b4 |
14 | 642582756b |
15 | 35b8973d9d |
hex | 1e4be4e69b |
130122311323 has 4 divisors (see below), whose sum is σ = 130662238168. Its totient is φ = 129582384480.
The previous prime is 130122311321. The next prime is 130122311369. The reversal of 130122311323 is 323113221031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130122311323 - 21 = 130122311321 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130122311294 and 130122311303.
It is not an unprimeable number, because it can be changed into a prime (130122311321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 269963061 + ... + 269963542.
It is an arithmetic number, because the mean of its divisors is an integer number (32665559542).
Almost surely, 2130122311323 is an apocalyptic number.
130122311323 is a deficient number, since it is larger than the sum of its proper divisors (539926845).
130122311323 is an equidigital number, since it uses as much as digits as its factorization.
130122311323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 539926844.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 130122311323 its reverse (323113221031), we get a palindrome (453235532354).
The spelling of 130122311323 in words is "one hundred thirty billion, one hundred twenty-two million, three hundred eleven thousand, three hundred twenty-three".
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