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1301230113 = 31972201743
BaseRepresentation
bin100110110001111…
…0011001000100001
310100200111100010220
41031203303020201
510131103330423
6333041513253
744150162541
oct11543631041
93320440126
101301230113
11608568497
12303942829
13179778b61
14c4b61321
15793849e3
hex4d8f3221

1301230113 has 8 divisors (see below), whose sum is σ = 1743781248. Its totient is φ = 863082864.

The previous prime is 1301230111. The next prime is 1301230121. The reversal of 1301230113 is 3110321031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1301230113 - 21 = 1301230111 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1301230092 and 1301230101.

It is not an unprimeable number, because it can be changed into a prime (1301230111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1100281 + ... + 1101462.

It is an arithmetic number, because the mean of its divisors is an integer number (217972656).

Almost surely, 21301230113 is an apocalyptic number.

It is an amenable number.

1301230113 is a deficient number, since it is larger than the sum of its proper divisors (442551135).

1301230113 is a wasteful number, since it uses less digits than its factorization.

1301230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2201943.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 1301230113 is about 36072.5673192247. The cubic root of 1301230113 is about 1091.7370146872.

Adding to 1301230113 its reverse (3110321031), we get a palindrome (4411551144).

The spelling of 1301230113 in words is "one billion, three hundred one million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 197 591 2201743 6605229 433743371 1301230113