Base | Representation |
---|---|
bin | 11101100101100010110010… |
… | …100000010011001100110010 |
3 | 122001201200001011220011120102 |
4 | 131211202302200103030302 |
5 | 114023420031421330224 |
6 | 1140425455123312402 |
7 | 36260046162413114 |
oct | 3545426240231462 |
9 | 561650034804512 |
10 | 130123324011314 |
11 | 38508aa0107237 |
12 | 12716931b1b702 |
13 | 577b76630aa4a |
14 | 241c006b713b4 |
15 | 1009c162964ae |
hex | 7658b2813332 |
130123324011314 has 4 divisors (see below), whose sum is σ = 195184986016974. Its totient is φ = 65061662005656.
The previous prime is 130123324011313. The next prime is 130123324011347. The reversal of 130123324011314 is 413110423321031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 75168605220289 + 54954718791025 = 8669983^2 + 7413145^2 .
It is not an unprimeable number, because it can be changed into a prime (130123324011313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32530831002827 + ... + 32530831002830.
Almost surely, 2130123324011314 is an apocalyptic number.
130123324011314 is a deficient number, since it is larger than the sum of its proper divisors (65061662005660).
130123324011314 is an equidigital number, since it uses as much as digits as its factorization.
130123324011314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65061662005659.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 130123324011314 its reverse (413110423321031), we get a palindrome (543233747332345).
The spelling of 130123324011314 in words is "one hundred thirty trillion, one hundred twenty-three billion, three hundred twenty-four million, eleven thousand, three hundred fourteen".
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