Base | Representation |
---|---|
bin | 11101100101100011011101… |
… | …101011010111010111111011 |
3 | 122001201201220122211111010222 |
4 | 131211203131223113113323 |
5 | 114023423022333113113 |
6 | 1140430055040130255 |
7 | 36260103136141055 |
oct | 3545433553272773 |
9 | 561651818744128 |
10 | 130124048332283 |
11 | 38509331a58305 |
12 | 12716ab460698b |
13 | 577b8503b4235 |
14 | 241c07503a8d5 |
15 | 1009c59b6ee08 |
hex | 7658ddad75fb |
130124048332283 has 2 divisors, whose sum is σ = 130124048332284. Its totient is φ = 130124048332282.
The previous prime is 130124048332279. The next prime is 130124048332357. The reversal of 130124048332283 is 382233840421031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130124048332283 - 22 = 130124048332279 is a prime.
It is not a weakly prime, because it can be changed into another prime (130124048332783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65062024166141 + 65062024166142.
It is an arithmetic number, because the mean of its divisors is an integer number (65062024166142).
Almost surely, 2130124048332283 is an apocalyptic number.
130124048332283 is a deficient number, since it is larger than the sum of its proper divisors (1).
130124048332283 is an equidigital number, since it uses as much as digits as its factorization.
130124048332283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 663552, while the sum is 44.
The spelling of 130124048332283 in words is "one hundred thirty trillion, one hundred twenty-four billion, forty-eight million, three hundred thirty-two thousand, two hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •