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13013003545103 = 436725571766459
BaseRepresentation
bin1011110101011101001101…
…1101000010101000001111
31201002000211120222001201002
42331113103131002220033
53201201112401420403
643402031415410515
72512105234042532
oct275272335025017
951060746861632
1013013003545103
114167869286691
121562010683a3b
137351759cb8c3
1432db93034a19
15178771089188
hexbd5d3742a0f

13013003545103 has 16 divisors (see below), whose sum is σ = 13519665202560. Its totient is φ = 12515764748256.

The previous prime is 13013003545097. The next prime is 13013003545111. The reversal of 13013003545103 is 30154530031031.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13013003545103 is a prime.

It is a super-2 number, since 2×130130035451032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13013003545153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6483488 + ... + 8249946.

It is an arithmetic number, because the mean of its divisors is an integer number (844979075160).

Almost surely, 213013003545103 is an apocalyptic number.

13013003545103 is a deficient number, since it is larger than the sum of its proper divisors (506661657457).

13013003545103 is a wasteful number, since it uses less digits than its factorization.

13013003545103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1769126.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 13013003545103 its reverse (30154530031031), we get a palindrome (43167533576134).

The spelling of 13013003545103 in words is "thirteen trillion, thirteen billion, three million, five hundred forty-five thousand, one hundred three".

Divisors: 1 43 67 2557 2881 109951 171319 1766459 7366717 75957737 118352753 4516835663 5089168379 194223933509 302627989421 13013003545103