1301301001123 has 4 divisors (see below), whose sum is σ = 1301653565368. Its totient is φ = 1300948436880.

The previous prime is 1301301001069. The next prime is 1301301001127. The reversal of 1301301001123 is 3211001031031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1301301001123 is a prime.

It is a super-2 number, since 2×1301301001123² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301301001097 and 1301301001106.

It is not an unprimeable number, because it can be changed into a prime (1301301001127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176276586 + ... + 176283967.

It is an arithmetic number, because the mean of its divisors is an integer number (325413391342).

Almost surely, 2^{1301301001123} is an apocalyptic number.

1301301001123 is a deficient number, since it is larger than the sum of its proper divisors (352564245).

1301301001123 is an equidigital number, since it uses as much as digits as its factorization.

1301301001123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 352564244.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1301301001123 its reverse (3211001031031), we get a palindrome (4512302032154).

The spelling of 1301301001123 in words is "one trillion, three hundred one billion, three hundred one million, one thousand, one hundred twenty-three".