Base | Representation |
---|---|
bin | 10010111011111011100… |
… | …101110000000110101001 |
3 | 11121101212220121020012221 |
4 | 102323323211300012221 |
5 | 132310031040212334 |
6 | 2433450502434041 |
7 | 163005311565562 |
oct | 22737345600651 |
9 | 4541786536187 |
10 | 1301301100969 |
11 | 461973601651 |
12 | 19024b132921 |
13 | 9593482957c |
14 | 46daa2b5169 |
15 | 23cb32818b4 |
hex | 12efb9701a9 |
1301301100969 has 2 divisors, whose sum is σ = 1301301100970. Its totient is φ = 1301301100968.
The previous prime is 1301301100937. The next prime is 1301301101057. The reversal of 1301301100969 is 9690011031031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 757117515625 + 544183585344 = 870125^2 + 737688^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301301100969 - 25 = 1301301100937 is a prime.
It is a super-2 number, since 2×13013011009692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1301301100069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650650550484 + 650650550485.
It is an arithmetic number, because the mean of its divisors is an integer number (650650550485).
Almost surely, 21301301100969 is an apocalyptic number.
It is an amenable number.
1301301100969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301301100969 is an equidigital number, since it uses as much as digits as its factorization.
1301301100969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 34.
The spelling of 1301301100969 in words is "one trillion, three hundred one billion, three hundred one million, one hundred thousand, nine hundred sixty-nine".
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