Base | Representation |
---|---|
bin | 1011110101011101011000… |
… | …1110101101011101100011 |
3 | 1201002000221211121022111120 |
4 | 2331113112032231131203 |
5 | 3201201211312320120 |
6 | 43402040201543323 |
7 | 2512106340653520 |
oct | 275272616553543 |
9 | 51060854538446 |
10 | 13013050120035 |
11 | 41678925a8069 |
12 | 15620241a4b43 |
13 | 735182558034 |
14 | 32db992ba147 |
15 | 1787751d9140 |
hex | bd5d63ad763 |
13013050120035 has 32 divisors (see below), whose sum is σ = 23798183462400. Its totient is φ = 5948099958528.
The previous prime is 13013050119967. The next prime is 13013050120039. The reversal of 13013050120035 is 53002105031031.
It is not a de Polignac number, because 13013050120035 - 219 = 13013049595747 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13013050119987 and 13013050120014.
It is not an unprimeable number, because it can be changed into a prime (13013050120039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6662185 + ... + 8391114.
It is an arithmetic number, because the mean of its divisors is an integer number (743693233200).
Almost surely, 213013050120035 is an apocalyptic number.
13013050120035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13013050120035 is a deficient number, since it is larger than the sum of its proper divisors (10785133342365).
13013050120035 is a wasteful number, since it uses less digits than its factorization.
13013050120035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15061547.
The product of its (nonzero) digits is 1350, while the sum is 24.
Adding to 13013050120035 its reverse (53002105031031), we get a palindrome (66015155151066).
The spelling of 13013050120035 in words is "thirteen trillion, thirteen billion, fifty million, one hundred twenty thousand, thirty-five".
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