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130131033410137 is a prime number
BaseRepresentation
bin11101100101101001111110…
…000001010100101001011001
3122001202101221110111012121011
4131211221332001110221121
5114024031324023111022
61140433212122413521
736260441214260404
oct3545517601245131
9561671843435534
10130131033410137
113851129693a721
12127183239612a1
13577c3c45940b6
14241c5389d0d3b
15100a017edc977
hex765a7e054a59

130131033410137 has 2 divisors, whose sum is σ = 130131033410138. Its totient is φ = 130131033410136.

The previous prime is 130131033410099. The next prime is 130131033410149. The reversal of 130131033410137 is 731014330131031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123327887985481 + 6803145424656 = 11105309^2 + 2608284^2 .

It is a cyclic number.

It is not a de Polignac number, because 130131033410137 - 219 = 130131032885849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130131033410099 and 130131033410108.

It is not a weakly prime, because it can be changed into another prime (130131033410197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65065516705068 + 65065516705069.

It is an arithmetic number, because the mean of its divisors is an integer number (65065516705069).

Almost surely, 2130131033410137 is an apocalyptic number.

It is an amenable number.

130131033410137 is a deficient number, since it is larger than the sum of its proper divisors (1).

130131033410137 is an equidigital number, since it uses as much as digits as its factorization.

130131033410137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 31.

Adding to 130131033410137 its reverse (731014330131031), we get a palindrome (861145363541168).

The spelling of 130131033410137 in words is "one hundred thirty trillion, one hundred thirty-one billion, thirty-three million, four hundred ten thousand, one hundred thirty-seven".