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130132143555553 is a prime number
BaseRepresentation
bin11101100101101011000000…
…001100001100001111100001
3122001202111210211102102211001
4131211223000030030033201
5114024041112222234203
61140433514220552001
736260510554330066
oct3545530014141741
9561674724372731
10130132143555553
1138511806554377
12127185936b2601
13577c540587889
14241c602210c6d
15100a0806c991d
hex765ac030c3e1

130132143555553 has 2 divisors, whose sum is σ = 130132143555554. Its totient is φ = 130132143555552.

The previous prime is 130132143555541. The next prime is 130132143555611. The reversal of 130132143555553 is 355555341231031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124028046956944 + 6104096598609 = 11136788^2 + 2470647^2 .

It is an emirp because it is prime and its reverse (355555341231031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130132143555553 - 25 = 130132143555521 is a prime.

It is not a weakly prime, because it can be changed into another prime (130132143553553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066071777776 + 65066071777777.

It is an arithmetic number, because the mean of its divisors is an integer number (65066071777777).

Almost surely, 2130132143555553 is an apocalyptic number.

It is an amenable number.

130132143555553 is a deficient number, since it is larger than the sum of its proper divisors (1).

130132143555553 is an equidigital number, since it uses as much as digits as its factorization.

130132143555553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2025000, while the sum is 46.

Adding to 130132143555553 its reverse (355555341231031), we get a palindrome (485687484786584).

The spelling of 130132143555553 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred forty-three million, five hundred fifty-five thousand, five hundred fifty-three".