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13013310010633 is a prime number
BaseRepresentation
bin1011110101011110010110…
…1110000111010100001001
31201002001121221122010101021
42331113211232013110021
53201202224330320013
643402122044152441
72512115645001202
oct275274556072411
951061557563337
1013013310010633
114167a06276789
121562097238721
137351c435155a
1432dbc1a0c5a9
1517878ce23a8d
hexbd5e5b87509

13013310010633 has 2 divisors, whose sum is σ = 13013310010634. Its totient is φ = 13013310010632.

The previous prime is 13013310010549. The next prime is 13013310010639. The reversal of 13013310010633 is 33601001331031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7601694151689 + 5411615858944 = 2757117^2 + 2326288^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13013310010633 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13013310010598 and 13013310010607.

It is not a weakly prime, because it can be changed into another prime (13013310010639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506655005316 + 6506655005317.

It is an arithmetic number, because the mean of its divisors is an integer number (6506655005317).

Almost surely, 213013310010633 is an apocalyptic number.

It is an amenable number.

13013310010633 is a deficient number, since it is larger than the sum of its proper divisors (1).

13013310010633 is an equidigital number, since it uses as much as digits as its factorization.

13013310010633 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 13013310010633 its reverse (33601001331031), we get a palindrome (46614311341664).

The spelling of 13013310010633 in words is "thirteen trillion, thirteen billion, three hundred ten million, ten thousand, six hundred thirty-three".