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130134401040113 is a prime number
BaseRepresentation
bin11101100101101101000110…
…101111110011111011110001
3122001202201122011021112110022
4131211231012233303323301
5114024110223131240423
61140434530222413225
736260620525535531
oct3545550657637361
9561681564245408
10130134401040113
1138512764876998
1212718b03731215
13577c810195262
14241c777d734c1
15100a16399ddc8
hex765b46bf3ef1

130134401040113 has 2 divisors, whose sum is σ = 130134401040114. Its totient is φ = 130134401040112.

The previous prime is 130134401040079. The next prime is 130134401040187. The reversal of 130134401040113 is 311040104431031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94978122731584 + 35156278308529 = 9745672^2 + 5929273^2 .

It is a cyclic number.

It is not a de Polignac number, because 130134401040113 - 28 = 130134401039857 is a prime.

It is not a weakly prime, because it can be changed into another prime (130134401049113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65067200520056 + 65067200520057.

It is an arithmetic number, because the mean of its divisors is an integer number (65067200520057).

Almost surely, 2130134401040113 is an apocalyptic number.

It is an amenable number.

130134401040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

130134401040113 is an equidigital number, since it uses as much as digits as its factorization.

130134401040113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 130134401040113 its reverse (311040104431031), we get a palindrome (441174505471144).

The spelling of 130134401040113 in words is "one hundred thirty trillion, one hundred thirty-four billion, four hundred one million, forty thousand, one hundred thirteen".