Base | Representation |
---|---|
bin | 1011110101011111100110… |
… | …0011000001011110010011 |
3 | 1201002002111010112211022010 |
4 | 2331113321203001132103 |
5 | 3201203420004204233 |
6 | 43402215045514003 |
7 | 2512130124240624 |
oct | 275277143013623 |
9 | 51062433484263 |
10 | 13013642647443 |
11 | 4168067011739 |
12 | 156216a712903 |
13 | 735248238579 |
14 | 32dc13c79a4b |
15 | 1787ac22cb63 |
hex | bd5f98c1793 |
13013642647443 has 4 divisors (see below), whose sum is σ = 17351523529928. Its totient is φ = 8675761764960.
The previous prime is 13013642647433. The next prime is 13013642647451. The reversal of 13013642647443 is 34474624631031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13013642647443 - 29 = 13013642646931 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13013642647392 and 13013642647401.
It is not an unprimeable number, because it can be changed into a prime (13013642647433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2168940441238 + ... + 2168940441243.
It is an arithmetic number, because the mean of its divisors is an integer number (4337880882482).
Almost surely, 213013642647443 is an apocalyptic number.
13013642647443 is a deficient number, since it is larger than the sum of its proper divisors (4337880882485).
13013642647443 is an equidigital number, since it uses as much as digits as its factorization.
13013642647443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4337880882484.
The product of its (nonzero) digits is 3483648, while the sum is 48.
The spelling of 13013642647443 in words is "thirteen trillion, thirteen billion, six hundred forty-two million, six hundred forty-seven thousand, four hundred forty-three".
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