Base | Representation |
---|---|
bin | 1011110101100000111011… |
… | …1010011101111111111011 |
3 | 1201002010102010001212112011 |
4 | 2331120032322131333323 |
5 | 3201210133241141011 |
6 | 43402314413030351 |
7 | 2512142036203132 |
oct | 275301672357773 |
9 | 51063363055464 |
10 | 13014001115131 |
11 | 416823039a825 |
12 | 156224a7853b7 |
13 | 7352a4597a23 |
14 | 32dc4970c919 |
15 | 1787cd93a621 |
hex | bd60ee9dffb |
13014001115131 has 2 divisors, whose sum is σ = 13014001115132. Its totient is φ = 13014001115130.
The previous prime is 13014001115119. The next prime is 13014001115173. The reversal of 13014001115131 is 13151110041031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13014001115131 - 211 = 13014001113083 is a prime.
It is a super-2 number, since 2×130140011151312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13014001115191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507000557565 + 6507000557566.
It is an arithmetic number, because the mean of its divisors is an integer number (6507000557566).
Almost surely, 213014001115131 is an apocalyptic number.
13014001115131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13014001115131 is an equidigital number, since it uses as much as digits as its factorization.
13014001115131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 22.
Adding to 13014001115131 its reverse (13151110041031), we get a palindrome (26165111156162).
The spelling of 13014001115131 in words is "thirteen trillion, fourteen billion, one million, one hundred fifteen thousand, one hundred thirty-one".
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