130141300254131 has 2 divisors, whose sum is σ = 130141300254132. Its totient is φ = 130141300254130.

The previous prime is 130141300254101. The next prime is 130141300254149. The reversal of 130141300254131 is 131452003141031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130141300254131 - 2¹⁴ = 130141300237747 is a prime.

It is a super-2 number, since 2×130141300254131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130141300254094 and 130141300254103.

It is not a weakly prime, because it can be changed into another prime (130141300254101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65070650127065 + 65070650127066.

It is an arithmetic number, because the mean of its divisors is an integer number (65070650127066).

Almost surely, 2^{130141300254131} is an apocalyptic number.

130141300254131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130141300254131 is an equidigital number, since it uses as much as digits as its factorization.

130141300254131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 130141300254131 its reverse (131452003141031), we get a palindrome (261593303395162).

The spelling of 130141300254131 in words is "one hundred thirty trillion, one hundred forty-one billion, three hundred million, two hundred fifty-four thousand, one hundred thirty-one".