1301414411131 has 4 divisors (see below), whose sum is σ = 1336587773632. Its totient is φ = 1266241048632.

The previous prime is 1301414411123. The next prime is 1301414411153. The reversal of 1301414411131 is 1311144141031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301414411131 - 2³ = 1301414411123 is a prime.

It is a super-2 number, since 2×1301414411131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301414411096 and 1301414411105.

It is not an unprimeable number, because it can be changed into a prime (1301414411111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17586681195 + ... + 17586681268.

It is an arithmetic number, because the mean of its divisors is an integer number (334146943408).

Almost surely, 2^{1301414411131} is an apocalyptic number.

1301414411131 is a deficient number, since it is larger than the sum of its proper divisors (35173362501).

1301414411131 is an equidigital number, since it uses as much as digits as its factorization.

1301414411131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35173362500.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 1301414411131 its reverse (1311144141031), we get a palindrome (2612558552162).

The spelling of 1301414411131 in words is "one trillion, three hundred one billion, four hundred fourteen million, four hundred eleven thousand, one hundred thirty-one".