Base | Representation |
---|---|
bin | 11101100101110101001111… |
… | …110001010001111001000111 |
3 | 122001210120012100121022112010 |
4 | 131211311033301101321013 |
5 | 114024231123420321003 |
6 | 1140442533443225303 |
7 | 36261350250511245 |
oct | 3545651761217107 |
9 | 561716170538463 |
10 | 130143142354503 |
11 | 38516440041863 |
12 | 1271a743078233 |
13 | 57805a4181635 |
14 | 241cd66c8b795 |
15 | 100a4c60cd003 |
hex | 765d4fc51e47 |
130143142354503 has 16 divisors (see below), whose sum is σ = 176490353385216. Its totient is φ = 85286265348480.
The previous prime is 130143142354501. The next prime is 130143142354541. The reversal of 130143142354503 is 305453241341031.
It is not a de Polignac number, because 130143142354503 - 21 = 130143142354501 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130143142354501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 906457401 + ... + 906600962.
It is an arithmetic number, because the mean of its divisors is an integer number (11030647086576).
Almost surely, 2130143142354503 is an apocalyptic number.
130143142354503 is a deficient number, since it is larger than the sum of its proper divisors (46347211030713).
130143142354503 is a wasteful number, since it uses less digits than its factorization.
130143142354503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1813058774.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 130143142354503 its reverse (305453241341031), we get a palindrome (435596383695534).
The spelling of 130143142354503 in words is "one hundred thirty trillion, one hundred forty-three billion, one hundred forty-two million, three hundred fifty-four thousand, five hundred three".
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