Base | Representation |
---|---|
bin | 10010111100000011011… |
… | …001001001001001011011 |
3 | 11121102020000221021022121 |
4 | 102330003121021021123 |
5 | 132310313043412103 |
6 | 2433511500402111 |
7 | 163011461406514 |
oct | 22740331111133 |
9 | 4542200837277 |
10 | 1301432013403 |
11 | 461a30497045 |
12 | 190286b46337 |
13 | 959559a4452 |
14 | 46dbd831a0b |
15 | 23cbe9e06bd |
hex | 12f0364925b |
1301432013403 has 8 divisors (see below), whose sum is σ = 1328959796288. Its totient is φ = 1274142566664.
The previous prime is 1301432013377. The next prime is 1301432013439. The reversal of 1301432013403 is 3043102341031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301432013403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1301432013803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59573001 + ... + 59594842.
It is an arithmetic number, because the mean of its divisors is an integer number (166119974536).
Almost surely, 21301432013403 is an apocalyptic number.
1301432013403 is a deficient number, since it is larger than the sum of its proper divisors (27527782885).
1301432013403 is a wasteful number, since it uses less digits than its factorization.
1301432013403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119168073.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1301432013403 its reverse (3043102341031), we get a palindrome (4344534354434).
The spelling of 1301432013403 in words is "one trillion, three hundred one billion, four hundred thirty-two million, thirteen thousand, four hundred three".
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