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1301432013403 = 67163119167843
BaseRepresentation
bin10010111100000011011…
…001001001001001011011
311121102020000221021022121
4102330003121021021123
5132310313043412103
62433511500402111
7163011461406514
oct22740331111133
94542200837277
101301432013403
11461a30497045
12190286b46337
13959559a4452
1446dbd831a0b
1523cbe9e06bd
hex12f0364925b

1301432013403 has 8 divisors (see below), whose sum is σ = 1328959796288. Its totient is φ = 1274142566664.

The previous prime is 1301432013377. The next prime is 1301432013439. The reversal of 1301432013403 is 3043102341031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1301432013403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301432013803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59573001 + ... + 59594842.

It is an arithmetic number, because the mean of its divisors is an integer number (166119974536).

Almost surely, 21301432013403 is an apocalyptic number.

1301432013403 is a deficient number, since it is larger than the sum of its proper divisors (27527782885).

1301432013403 is a wasteful number, since it uses less digits than its factorization.

1301432013403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119168073.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1301432013403 its reverse (3043102341031), we get a palindrome (4344534354434).

The spelling of 1301432013403 in words is "one trillion, three hundred one billion, four hundred thirty-two million, thirteen thousand, four hundred three".

Divisors: 1 67 163 10921 119167843 7984245481 19424358409 1301432013403