130145015203433 has 2 divisors, whose sum is σ = 130145015203434. Its totient is φ = 130145015203432.

The previous prime is 130145015203393. The next prime is 130145015203471. The reversal of 130145015203433 is 334302510541031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128562217206784 + 1582797996649 = 11338528^2 + 1258093^2 .

It is an emirp because it is prime and its reverse (334302510541031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130145015203433 - 2²⁴ = 130144998426217 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130145015203393 and 130145015203402.

It is not a weakly prime, because it can be changed into another prime (130145015203733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65072507601716 + 65072507601717.

It is an arithmetic number, because the mean of its divisors is an integer number (65072507601717).

Almost surely, 2^{130145015203433} is an apocalyptic number.

It is an amenable number.

130145015203433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130145015203433 is an equidigital number, since it uses as much as digits as its factorization.

130145015203433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 130145015203433 its reverse (334302510541031), we get a palindrome (464447525744464).

The spelling of 130145015203433 in words is "one hundred thirty trillion, one hundred forty-five billion, fifteen million, two hundred three thousand, four hundred thirty-three".