Base | Representation |
---|---|
bin | 11101100101110111011111… |
… | …010010100100110011011011 |
3 | 122001210210102011102210100012 |
4 | 131211313133102210303123 |
5 | 114024301041324141403 |
6 | 1140444012420232135 |
7 | 36261464026203554 |
oct | 3545673722446333 |
9 | 561723364383305 |
10 | 130145550224603 |
11 | 3851746623a251 |
12 | 1271b0b553b64b |
13 | 5780898c94544 |
14 | 241d11499932b |
15 | 100a5b76aaed8 |
hex | 765ddf4a4cdb |
130145550224603 has 2 divisors, whose sum is σ = 130145550224604. Its totient is φ = 130145550224602.
The previous prime is 130145550224597. The next prime is 130145550224639. The reversal of 130145550224603 is 306422055541031.
It is a weak prime.
It is an emirp because it is prime and its reverse (306422055541031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130145550224603 - 26 = 130145550224539 is a prime.
It is not a weakly prime, because it can be changed into another prime (130145550224693) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65072775112301 + 65072775112302.
It is an arithmetic number, because the mean of its divisors is an integer number (65072775112302).
Almost surely, 2130145550224603 is an apocalyptic number.
130145550224603 is a deficient number, since it is larger than the sum of its proper divisors (1).
130145550224603 is an equidigital number, since it uses as much as digits as its factorization.
130145550224603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432000, while the sum is 41.
The spelling of 130145550224603 in words is "one hundred thirty trillion, one hundred forty-five billion, five hundred fifty million, two hundred twenty-four thousand, six hundred three".
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