Base | Representation |
---|---|
bin | 111100100110110010… |
… | …0011001000011101101 |
3 | 110102221101221120120200 |
4 | 1321031210121003231 |
5 | 4113022000414313 |
6 | 135442410504113 |
7 | 12255151116645 |
oct | 1711544310355 |
9 | 412841846520 |
10 | 130150404333 |
11 | 50218568134 |
12 | 21283135039 |
13 | c3720b5791 |
14 | 642945b525 |
15 | 35bb172b73 |
hex | 1e4d9190ed |
130150404333 has 96 divisors (see below), whose sum is σ = 201812083200. Its totient is φ = 80684771328.
The previous prime is 130150404317. The next prime is 130150404361. The reversal of 130150404333 is 333404051031.
It is not a de Polignac number, because 130150404333 - 24 = 130150404317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130150404297 and 130150404306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130150404133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 300578085 + ... + 300578517.
It is an arithmetic number, because the mean of its divisors is an integer number (2102209200).
Almost surely, 2130150404333 is an apocalyptic number.
It is an amenable number.
130150404333 is a deficient number, since it is larger than the sum of its proper divisors (71661678867).
130150404333 is a wasteful number, since it uses less digits than its factorization.
130150404333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 851 (or 848 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
Adding to 130150404333 its reverse (333404051031), we get a palindrome (463554455364).
The spelling of 130150404333 in words is "one hundred thirty billion, one hundred fifty million, four hundred four thousand, three hundred thirty-three".
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