Base | Representation |
---|---|
bin | 11101100101111110011011… |
… | …100001111111110001110001 |
3 | 122001211111122120210211220021 |
4 | 131211332123201333301301 |
5 | 114024411322324214103 |
6 | 1140451244142443441 |
7 | 36262146516553516 |
oct | 3545763341776161 |
9 | 561744576724807 |
10 | 130153003351153 |
11 | 3851a640345572 |
12 | 12720635593581 |
13 | 57814b61202b3 |
14 | 241d62078930d |
15 | 100a8a1b7ebbd |
hex | 765f9b87fc71 |
130153003351153 has 2 divisors, whose sum is σ = 130153003351154. Its totient is φ = 130153003351152.
The previous prime is 130153003351093. The next prime is 130153003351229. The reversal of 130153003351153 is 351153300351031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105528611834944 + 24624391516209 = 10272712^2 + 4962297^2 .
It is a cyclic number.
It is not a de Polignac number, because 130153003351153 - 213 = 130153003342961 is a prime.
It is not a weakly prime, because it can be changed into another prime (130153003351753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65076501675576 + 65076501675577.
It is an arithmetic number, because the mean of its divisors is an integer number (65076501675577).
Almost surely, 2130153003351153 is an apocalyptic number.
It is an amenable number.
130153003351153 is a deficient number, since it is larger than the sum of its proper divisors (1).
130153003351153 is an equidigital number, since it uses as much as digits as its factorization.
130153003351153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30375, while the sum is 34.
The spelling of 130153003351153 in words is "one hundred thirty trillion, one hundred fifty-three billion, three million, three hundred fifty-one thousand, one hundred fifty-three".
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